43.2k views
3 votes
The sum of 10 consecutive integersstarting with 11, equals the sum of 5 consecutive integers, starting with

(A) 22
(B) 29
(C) 31
(D) 33

User Bschneidr
by
4.9k points

1 Answer

4 votes

Answer:
\large\boxed{29}

Explanation:

The sum of 10 consecutive integersstarting with 11

= 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 155

Lets try 29:

29 + 30 + 31 + 32 + 33 = 155

Therefore our answer is:


\large\boxed{29}

User Jeldrik
by
5.6k points