Question

Im confuse gusy can u help me?

Answer 1

11. 333... which can also be written as 11 1/3.

Explanation:

Sure.

√(6c - 4) = 8

Squaring both sides:

6c - 4 = 64

6c = 64 + 4 = 68

c = 68/6

= 11. 333...

Answer 2

`c=(34)/(3)`

Explanation:

Given equation:

`√(6c-4)=8`

Square both sides:

`\implies (√(6c-4))^2=8^2`

`\implies 6c-4=64`

Add 4 to both sides:

`\implies 6c-4+4=64+4`

`\implies 6c=68`

Divide both sides by 6:

`\implies (6c)/(6)=(68)/(6)`

`\implies c=(34)/(3)`

Verify the solution by inputting the found value of c back into the equation:

`\implies \sqrt{6\left((34)/(3)\right)-4}`

`\implies \sqrt{(204)/(3)-4}`

`\implies √(68-4)`

`\implies √(64)`

`\implies \pm 8`

Therefore, the solution of the found value of c is verified.