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What mass of hydrogen is produced when 192 g of magnesium is reacted with hydrochloric acid?​

User Andygavin
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2 Answers

4 votes

Answer:

Mg+2HCL-Magnesium Chloride +Hygrogen


>

Step-by-step explanation:

N.O of moles=Mass\Molar Mass

192÷24=8

1:1

8×2=16

User Paachi
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2 votes


\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}


\longrightarrow \sf{Mg+2HCI \Longrightarrow MgCl_2+H_2}


\longrightarrow \sf{molMg=129gMg * (1molMg)/(24.305gMg=) }


\small \sf{\longrightarrow molH_2=7.90molMg * (1molH_2)/(1molMg)= 7.90molH_2 }


\small \sf{\longrightarrow massH_2=7.90H_2 * (2.016g)/(1molH_2)= 7.90molH_2= 15.9 \: gH_2}


\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}


\small\bm{ The \: mass \: of \:H_2 \: produce \: will \: be \: 15.9 }
\bm{grams.}

User Vusak
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