Question

The equilibrium constant for the following reaction:

Ca(HCO3)2(s) <--> CaO(s) + 2 CO2(g) + H2O(g)
would be:
Group of answer choices

A. K = [Ca(HCO3)2] / [CaO][CO2]2[H2O]

B. K = [CaO][CO2]2[H2O] / [Ca(HCO3)2]

C. K = [CO2]2[H2O]

D. K = [CO2]2[H2O] / [Ca(HCO3)2]

Answer 1

C.)
`K = {[CO_(2) ]^(2) [H_2O] }`

Step-by-step explanation:

The general equilibrium expression looks like this:

`K = ([B]^b[C]^(c) [D]^(d) )/([A]^(a)) }`

In this expression,

-----> K = equilibrium constant

-----> uppercase letters = formulas

-----> lowercase letters = balanced equation coefficients

Solids are not included in the expression, so Ca(HCO₃)₂(s) and CaO(s) should be left out. The products should be in the numerator and the reactants are in the denominator. This makes the expression:

`K = ([B]^b[C]^(c) [D]^(d) )/([A]^(a)) }` <----- Equilibrium expression

`K = {[CO_(2) ]^(c) [H_2O]^(d) }` <----- Insert gaseous formulas

`K = {[CO_(2) ]^(2) [H_2O] }` <----- Insert coefficients