Question

What is the equation of a line in point-slope form passing through (-4,6) and (2, 3)?

Answer 1

Answer: y=-0,5x+4.

Explanation:

`A(-4;6)\ \ \ \ B(2;3)\\Straight \ line\ equation\ is:\\\displaystyle\\\boxed {(x-x_1)/(x_2-x_1) =(y-y_1)/(y_2-y_1)} \\(x-(-4))/(2-(-4))=(y-6)/(3-6) \\ (x+4)/(2+4)=(y-6)/(-3) \\(x+4)/(6)=(y-6)/(-3) \\ Multiply\ the\ left\ and\ right\ sides\ of\ the\ equation \ by\ -3:\\(-(x+4))/(2) =y-6\\-0,5x-2=y-6\\y=-0,5x+4.`

Answer 2

The answer is y - 3 = -1/2 (x - 2).

First, let's find the slope.

• m = y₂ - y₁ / x₂ - x₁
• m = 3 - 6 / 2 + 4
• m = -3/6
• m = -1/2

Then, the point slope form will be :

• y - 3 = -1/2 (x - 2)