Question

Find the 37th term of the arithmetic sequence 412,404,396

Answer 1

124

Explanation:

Is an arithmetic sequence so we know we need to add or subtract something

we see the numbers get lower we need to subtract something

a1=412, a2 = 412-8= 404, a3 =404-8 = 396

so the common difference d = (-8)

nth term = first term + position of the term· common difference

an = a1 + (n-1) · d

a37 = 412 + (37-1) · (-8)

a37 = 412+ 36(-8)

a37 = 412 -288

a37 = 124