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24 votes
24 votes
Evaluate: sigma 20 and 1 = (3n+2)
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User Igor Litvinovich
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1 Answer

8 votes
8 votes

Answer:

Explanation:


\displaystyle \sum_(n=1)^(20) (3n+2)=((62+5)*20)/(2) =10*67=670\\

User Carlo Zanocco
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