Question

1) A 20-foot ladder is placed against a building. If the top of the ladder will lean against the building 4sqrt(7) - f feet high, how far away from the base of the building is the bottom of the ladder located? Include a sketch that shows all known information and clearly shows what you need to findShow all work and give the exact answer

Answer 1

12√2.

Explanation:

You can do this by the Pythagoras theorem:

20^2 = x^2 + (4sqrt7)^2 where x is the distance required.

x^2 = 20^2 - (4sqrt7)^2

= 400 - 112

= 288

x = √288

= √144 *√2

= 12√2.