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Find the zeros of the following
1.x³+x²-4x-4=0

User Raoot
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1 Answer

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Answer:

x = -1, x = -2 , x= 2

Explanation:

First we factorise this cubic function :

(x+1)(x+2)(x-2) = 0

Using the law a×b×0 = 0

We know that to find the zeros we have to set each bracket equal to 0 :

x+1 = 0 OR x+2 = 0 OR x-2 = 0

x = -1 x = -2 x = 2

Hope this helped and have a good day

User Diego Vidal
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