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Kawan buys some protein bars at $0.90 each and bottled water at $0.70 each for a group hike. He buys twice as many bottles of water as protein bars. If he spends $46 in total, how many bottles of water and protein bars does he buy? Let x= the number of protein bars

User Pecata
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2 Answers

6 votes

Answer:

he buts 20 protein bars and 40 water bottles

Explanation:

so first u set up an equation like this

46=.90x+.70(2x)

next you multipy

46=.90x+1.4x

Then add

46=2.3x

then divide by 2.3 to solve for x

x=20 so u have 20 protein bars

and 20 times 2 to find the amount of water bottles

User Dreadbot
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5.3k points
3 votes

Answer:

20 Protein bars and 40 waters.

Explanation:

Let x = protein bars and y = waters

y = 2x .9x + .7 y = 46

Looking at the second equation, I would rather not work with decimals, so I will multiple the whole equation through by ten. That now gives m

9x + 7y = 460 Substitute in 2x for y (from my first equation above)

9x + 7(2x) = 460

9x +14x = 460 Combine 9x and 14x

23x = 460 Divide both sides by 23

x = 20 This is the number of protein bars. To find y plug 20 into the first equation above.

y = 2x

y =20(2)

y = 40

User Math Avengers
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4.2k points