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write an equation in slope -intercept form for the line that passes through the points (8,-3) and has a slope of 3 over 2

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Answer:

y = 3/2x -15

Explanation:

y = mx + b this is the slope intercept form. We need the slope and the y intercept. The slope (m) has been given (3/2), we just need the b (y-intercept). We will use the point given to find b. The point given is (8,-3). 8 is the x term and -3 is the y term. We will plug them into y = 3/2x + b to solve for b.

y = mx + b

y = (3/2) x + b The slope was given

-3 = (3/2)(8) + b Plugged in the given x and y from the point (8, -3)

-3 = 12 + b I can make 8 into a fraction by putting a 1 under it.

(3/2)(8/1). I can cross cancel to make the number easier to

2 and 8 both share the factor 2 so I will divide both numbers

by 2 and I will now have (3/1)(4/1). 3x4 is 12 and 1x1 is 1, so

12/1 is the same as 12.

-15 = b Subtract both sides by 12. -3-12 is -15

Now that I have the m and the b, I can write the equation in the slope intercept form. y = 3/2 + (-15) or y = 3/2 -15

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