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Local extreme Value for each of the Following A) F(x)=x^² - 4x² +5​

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3 votes

Answer:

max{x²-4x²+5} = 5 at x = 0

Explanation:

1. Find the critical numbers by finding the first derivative of f(x), set it to 0 and solve for x.


f'(x)=0

We get:


f(x) = -3x^2+5\\f'(x) = -6x\\-6x = 0\\x = 0

So the critical number is x = 0.

2. Evaluate the first derivative by plugging in the critical number and see if the derivative is positive or negative on both sides:


f'(x) is positive when the x < 0 (for example: -6*(-1)=+)


f'(x) is negative when the x > 0 (for example: -6*(1)=-)

Therefore, you have a local maximum.

Now just get the Y value by plugging in the critical number in the original function.
f(0)=5

local maximum is (0,5)

User Jxmallett
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