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A helium balloon has a volume of 2600 cm 3 when the temperature is 21°C. What is the

volume of the balloon when it's placed in a freezer with a temperature of -15°C?

1 Answer

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Answer:

2,282 cm³

Step-by-step explanation:

If all other variables are being held constant, you can find the new volume of the balloon using the Charles' Law equation. The equation looks like this:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. Before you can solve for the new volume, you need to convert Celsius to Kelvin (negative values do not work in this equation). This can be done by adding 273.15 to each temperature.

V₁ = 2600 cm³ V₂ = ? cm³

T₁ = 21 °C + 273.15 = 294.15 K T₂ = -15 °C + 273.15 = 258.15 K

V₁ / T₁ = V₂ / T₂ <----- Charles' Law

(2600 cm³) / (294.15 K) = V₂ / (258.15 K) <----- Insert values

8.839 = V₂ / (258.15 K) <----- Simplify left side

2282 = V₂ <----- Multiply both sides by 258.15

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