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The sum of series of 4+ 15 + 26 + ….. + 213

User Beanow
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Decompose the terms in the sum as


4 + 15 + 26 + \cdots + 213 = 4 + (4 + 11) + (4 + 2*11) + \cdots + (4 + 19*11)

so there are 20 terms in the sum. Then our sum simplifies to


4 + 15 + 26 + \cdots + 213 = 4*20 + (0+1+2+\cdots+19)*11

Now, if


S = 1 + 2 + 3 + \cdots + 17 + 18 + 19

we can reverse the order of terms to get the same sum,


S = 19 + 18 + 17 + \cdots + 3 + 2 + 1

so that doubling up the sum gives


2S = (1 + 19) + (2 + 18) + \cdots + (18 + 2) + (19 + 1) = 19*20 \implies S=19*10=190

So, our sum evaluates to


4 + 15 + 26 + \cdots + 213 = 4*20 + 190*11 = \boxed{2170}

User Andrey Maslov
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