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How do you prove tanθ-cotθ divided by tanθ+cotθ equals tan^2θ -1 divided by sec^2θ
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How do you prove tanθ-cotθ divided by tanθ+cotθ equals tan^2θ -1 divided by sec^2θ

User Lgn
by
8.3k points

1 Answer

10 votes

Answer:

see attachment for proof

Explanation:

See attachment for step-by-step. I've also attached proof of the trig identity I used.

How do you prove tanθ-cotθ divided by tanθ+cotθ equals tan^2θ -1 divided by sec^2θ-example-1
How do you prove tanθ-cotθ divided by tanθ+cotθ equals tan^2θ -1 divided by sec^2θ-example-2
User Luisenrique
by
8.1k points
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