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3 votes
Find all solutions to 2w^4 - 5w^2 + 2 = 0
asap please

User Shiri
by
6.9k points

1 Answer

3 votes

Answer:

w = ±
√(1/2) or w= ±
√(2)

Explanation:

if we say some variable y = w^2, we can rewrite the equation to:

2y^2 - 5y + 2 = 0

this can be factored into (2y-1)(y-2) = 0

putting w^2 back in the place of y, that's (2w^2 - 1)(w^2 - 2) = 0

The equation is a fourth degree polynomial, so there are four roots, or four values of w that will cause the equation to equal 0.

If 0 is multiplied by anything, the result is 0, so we set 2w^2 - 1 = 0 and solve for w, which is ±√1/2, then set w^2 - 2 = 0 to get w = ±√2 as our roots

the four solutions are ±√1/2 and ±√2

(because the positive counts as one solution and the negative another solution)

User Ehsan Mohammadi
by
5.8k points
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