Question

Quick algebra 1 assignment for 50 points!

Only answer if you know the answer, tysm!



1. Create 5 questions referencing “Zeros and Intercepts”Below is an example of one.

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Example :


Given: h(x) = -2x + 10
What are the x-intercepts and y-intercepts of h?

a. x-intercepts of (0,5) and y-intercepts of (10,0)

b. x-intercepts of (10,0) and y-intercepts of (0,5)

c. x-intercepts of (5,0) and y-intercepts of (0,10)

d. x-intercepts of (0,10) and y-intercepts of (5,0)
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2. Answer each question and write a brief step by step process on how you got the answer to each of your questions.

Answer 1

• y=-2x+10

x intercept:-

put y =0

• -2x+10=0
• -2x=-10
• x=5

(5,0)

y intercept

put x=0

• y=-2(0)+10
• y=10

(0,10)

option C

Answer 2

Question 1: Given a(x) = x + 5, what are the x-intercepts and y-intercepts of a?

a. x-intercept at (-5,0), y-intercept at (0,5)

b. x-intercept at (5,0), y-intercept at (0,-5)

c. x-intercept at (0,5), y-intercept at (5,0)

Answer: a

The x-intercept is the place where the graph touches the x-axis. Since the equation for the x-axis is just y=0, we can put in 0 for y to get it.

0 = x + 5

x = -5

Since x is -5 and y is 0, the x-intercept is at (-5,0).

The y-intercept is the place where the graph touches the y-axis. Since the equation for the y-axis is just x=0, we can put in 0 for x to get it.

y = 0 + 5

y = 5

Since x is 0 and y is 5, the y-intercept is at (0,5).

Question 2: Given b(x) = 2x + 1, what are the x-intercepts and y-intercepts of b?

a. x-intercept at (0.5, 0), y-intercept at (0, 2)

b. x-intercept at (-0.5,0), y-intercept at (0, 1)

c. x-intercept at (0, -0.5), y-intercept at (1,0)

Answer: b

The x-intercept is the place where the graph touches the x-axis. Since the equation for the x-axis is just y=0, we can put in 0 for y to get it.

0 = 2x + 1

x = -0.5

Since x is -0.5 and y is 0, the x-intercept is at (-0.5,0).

The y-intercept is the place where the graph touches the y-axis. Since the equation for the y-axis is just x=0, we can put in 0 for x to get it.

y = 2(0) + 1

y = 1

Since x is 0 and y is 1, the y-intercept is at (0,1).

Question 3: Given c(x) = 3x - 2, what are the x-intercepts and y-intercepts of c?

a. x-intercept at (-2,0), y-intercept at (0,2/3)

b. x-intercept at (0, 2), y-intercept at (3/2, 0)

c. x-intercept at (2/3, 0), y-intercept at (0, -2)

Answer: c

The x-intercept is the place where the graph touches the x-axis. Since the equation for the x-axis is just y=0, we can put in 0 for y to get it.

0 = 3x - 2

x =
`(2)/(3)`

Since x is 2/3 and y is 0, the x-intercept is at (2/3,0).

If the equation is in the form y = mx + b, the y-intercept will be b. The y-intercept also crosses the graph x = 0, so the y-intercept is (0, -2).

Question 4: Given d(x) = -x + 1, find the x-intercepts and y-intercepts of d.

a. x-intercept at (0, 1), y-intercept at (1,0)

b. x-intercept at (1, 0), y-intercept at (0, -1)

c. x-intercept at (1,0), y-intercept at (0,1)

Answer: c

The x-intercept is the place where the graph touches the x-axis. Since the equation for the x-axis is just y=0, we can put in 0 for y to get it.

0 = -x+1

x = -(-1) = 1

Since x is 1 and y is 0, the x-intercept is at (1,0).

If the equation is in the form y = mx + b, the y-intercept will be b. The y-intercept also crosses the graph x = 0, so the y-intercept is (0, 1).

Question 5: Given f(x) = -7x+5, find the x-intercepts and y-intercepts of f.

a. x-intercept at (-5/7, 0), y-intercept at (0, -7/5)

b. x-intercept at (5, 0), y-intercept at (0, 5/7)

c. x-intercept at (5/7, 0), y-intercept at (0, 5)

Answer: c

The x-intercept is the place where the graph touches the x-axis. Since the equation for the x-axis is just y=0, we can put in 0 for y to get it.

0 = -7x+5

x = -5/-7= 5/7

Since x is 5/7 and y is 0, the x-intercept is at (5/7,0).

If the equation is in the form y = mx + b, the y-intercept will be b. The y-intercept also crosses the graph x = 0, so the y-intercept is (0, 5).