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an athlete sprints from 150 m south of the finish line to 65 m south of the finish line in 5.0s what is his average velocity

User Angelin Nadar
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1 Answer

18 votes
18 votes
  • Total displacement=150-65m=85m
  • Time=5s


\\ \rm\longrightarrow Avg\:Velocity=(Total\:Displacement)/(Total\:Time)


\\ \rm\longrightarrow Avg\:Velocity=(85)/(5)


\\ \rm\longrightarrow Avg\:Velocity= 17m/s

User Phil Cross
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