Question

PLS HELP I REALLY NEED HELP

Answer 1

Length of line segment AB = 10 units

Midpoint of line segment AB = (2, 6)

Explanation:

To find length, apply the distance formula :

• AB = √(5 - (-1))² + (2 - 10)²
• AB = √36 + 64 = √100
• 
  `\fbox {AB = 10 units}`

To find the midpoint :

• M = (-1 + 5 / 2, 10 + 2 / 2)
• 
  `\fbox {Midpoint = (2, 6)}`

Answer 2

• a) AB = 10 units
• b) Midpoint is (2, 6)

===================

Given

• Points A( - 1, 10) and B(5, 2)

To find

• a) The length of AB
• b) The midpoint of AB

Solution

a) Use the distance formula:

`d = √((x_2-x_1)^2+(y_2-y_1)^2)`

Substitute the coordinates and calculate:

`d=√((5-(-1))^2+(2-10)^2) =√(6^2+(-8)^2) =√(36+64) =√(100) =10`

The distance is AB = 10 units

b) Use midpoint formula and find x and y- coordinates of this point:

`x= \cfrac{x_1+x_2}{2}` and
`y= \cfrac{y_1+y_2}{2}`

Substitute coordinates and find the midpoint:

`x= \cfrac{-1+5}{2} =2` and
`y= \cfrac{10+2}{2}=6`

The midpoint is (2, 6)