214k views
5 votes
Compare the graph of g(x) = -0.3x² + 7 with the graph of p(x) = x².

The graph of g(x) is wider.
The graph of q(x) opens downward and the graph of p(x) op
Both have the axis of symmetry x = 0.
The vertex of q(x) is (0, 7); the vertex of p(x) is (0, 0).
O The graph of q(x) is narrower.
The graph of q(x) opens downward and the graph of p(x) op
Both have the axis of symmetry x = 1.
The vertex of q(x) is (1, 7); the vertex of p(x) is (1, 0).
The graph of q(x) is wider.
Both graphs open upward.
Both have the axis of symmetry x = 1.
The vertex of q(x) is (1, 7); the vertex of p(x) is (1, 0).
The graph of q(x) is narrower.
Both graphs open downward.
Both have the axis of symmetry x = 0.
The vartov nf n/v) is in 7) the vartav nf n/v) ie in my

User Tulir
by
4.8k points

1 Answer

2 votes

Answer:

Explanation:

Below is the graphs of the given g(x) and p(x)

g(x) is green

p(x) is blue

The graph of g(x) is wider.

The graph of g(x) opens downward

Both have the axis of symmetry x = 0

The vertex of g(x) is (0, 7); the vertex of p(x) is (0, 0).

The graph of g(x) opens downward and the graph of p(x) opens upward

The graph of g(x) is wider.

User Ellisbben
by
4.0k points