Question

Consider the reaction below.

Upper N a superscript plus, plus upper C subscript 2 upper H subscript 3 upper O subscript 2 superscript minus (a q) plus upper H superscript plus, plus upper C l superscript minus right arrow upper N a superscript plus, plus upper C l superscript minus plus upper H upper subscript 2 upper H subscript 3 upper O subscript 2.

Which is the net ionic equation for the reaction?

Answer 1

D.) C₂H₃O₂⁻ (aq) + H⁺ ---> HC₂H₃O₂

Step-by-step explanation:

The net ionic equation shows the compounds/elements that directly involved in the reaction. These substances can be determined depending on where and how many times they appear in the equation. If the compounds/elements appear on both the reactants and products side of the equation, they will not be found it the net ionic equation.

Expanded Equation:

Na⁺ + C₂H₃O₂⁻ (aq) + H⁺ + Cl⁻ ---> Na⁺ + Cl⁻ + HC₂H₃O₂

Net Ionic Equation:

C₂H₃O₂⁻ (aq) + H⁺ ---> HC₂H₃O₂

Therefore, since Na⁺ and Cl⁻ are located on both sides, they are eliminated. This leaves only the C₂H₃O₂⁻ (aq), H⁺, and HC₂H₃O₂ left in the net ionic equation.