Question

At the amusement park, Jack bought child and adult tickets costing $1.50

and $2.50, respectively. He bought a total of 9 tickets and paid $16.50.
How many of each kind of ticket did he buy?

Answer 1

Answer:

Explanation:
x=1.50 (child tickets)
y= 2.50 (adult tickets)

There’s a total of 9 tickets, therefore
possible options are:
1x+8y=16.50
2x+7y=16.50
3x+6y=16.50
4x+5y=16.50
5x+4y=16.50
6x+3y=16.50 …

I would then pick one and try it out and see if it works…

Let’s try 6x+3y=16.50
Substitute x= 1.50 and y=2.50 info the equation

6(1.50)+3(2.50)=16.50
9.0+7.5=16.50

Therefore, Jack bought 6 child tickets and 3 adult tickets. Hope this helps!