Register
The population of Nowhere, USA was estimated to be 886,000 in 2004, with an expected increase of 4% per year. At the percent of increase given, what was the expected population in 2005? Round your answer
65.2k views
3 votes
The population of Nowhere, USA was estimated to be 886,000 in 2004, with an expected increase of 4% per year. At the percent of increase given, what was the expected population in 2005? Round your answer to the nearest whole number.

User Nguyendown
by
5.8k points

1 Answer

0 votes

Answer:

y=886000(1.04)^t

t=1 year so answer is 886000*1.04 = 921440

User Maribeth
by
6.3k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

6.5m questions

8.6m answers

Other Questions

What is the least common denominator of the four fractions 20 7/10 20 3/4 18 9/10 20 18/25
What is 0.12 expressed as a fraction in simplest form
Solve using square root or factoring method plz help!!!!.....must click on pic to see the whole problem
What is the initial value and what does it represent? $4, the cost per item $4, the cost of the catalog $6, the cost per item $6, the cost of the catalog?
What is distributive property ?
Link Copied!