Question

Estimate the slope of the tangent line of the function y(t)=\sqrt{(3t+1} at the point t=2.

(Use decimal notation. Give your answer to three decimal places.)

Answer 1

Answer: 0.567

Explanation:

`y(t)=√(3t+1) \\\\y'(t)=(3)/(2√(3t+1) ) \\\\y'(2)=(3)/(2√(3*2+1) ) =(3√(7) )/(14) =0,56694670951384084082177480435127\approx{0.567}`