Question

a box has length 9.0cm width 6.0 and height 10.2cm.find the total surface area of the box and the volume of the box​

Answer 1

The total surface area of the box is 629.4 cm² and the volume is 547.2 cm³.

Step-by-step explanation:

To find the total surface area of the box, you need to find the areas of all six sides and add them together. The formula for the surface area of a rectangular box is SA = 2lw + 2lh + 2wh, where l is the length, w is the width, and h is the height. Plugging in the given values, we have:

SA = 2(9.0)(6.0) + 2(9.0)(10.2) + 2(6.0)(10.2) = 324 + 183.6 + 122.4 = 629.4 cm²

To find the volume of the box, you multiply the length, width, and height together. The formula for the volume of a rectangular box is V = lwh. Plugging in the given values, we have:

V = 9.0(6.0)(10.2) = 547.2 cm³

Answer 2

Total surface area : 207cm²

Volume : 550.8³

Step-by-step explanation:

Surface area, first need to work out the area of each face.

A box is symmetrical so some faces will be the same.

Area = Base × Height

Top/bottom : 9 × 6 = 54cm²

side/side = 6 × 10.2 = 61.2cm²

Front/Back = 9 × 10.2 = 91.8cm²

Add then all together

54 + 61.2 + 91.8 = 207cm²

Volume = base × height × width

9 × 6 × 10.2 =550.8cm³