Question

5.

Mr. Robson bought bags of orange for =N=2,500 each. He sold them for=N=90,000 at a loss of
How many bags of orange did he buy?
20%
(A) 60
(B)
80
(C) 50
(DY 45
The
CAL​

Answer 1

45

Explanation:

Let us assume the Bags of oranges be x

Now the cost price is 2500x

Sale price N = 90,000

Loss =20%

As we know that

Cost price= selling price × 100/ 100-percentage loss

= 90,000 × 100/ 100- 20

= 90,000 × 100 /80

Cost price= 112,500

Now

The Number of bags of oranges is

= 112,500 ÷ 2500

= 45