Question

What is the acceleration of a runner who increases her velocity from 2m/s to 8m/s in 3s?

Answer 1

Answer: 2 m/s^2

Step-by-step explanation:

V1-Vf/ T

2m/s - 8m/s / 3s

6m/s / 3s =

2 m/s^2

Answer 2

• initial velocity=u=2m/s
• Final velocity=v=8m/s
• Time=t=3s

`\\ \sf\longmapsto Acceleration=(v-u)/(t)`

`\\ \sf\longmapsto Acceleration=(8-2)/(3)`

`\\ \sf\longmapsto Acceleration=(6)/(3)`

`\\ \sf\longmapsto Acceleration=2m/s^2`