Question

Find the inverse of square root f(n) = n – 3.

Of(n) = (n + 3)
Of-1 (n) = yn +1
Of-1 (n) = -n° +1
Of-1 (n) = -n3 – 3

Answer 1

`f'(n) = n + 3`

Explanation:

Given

`f(n) = n - 3`

Required

The inverse

`f(n) = n - 3`

Replace f(n) with y

`y = n - 3`

Swap positions of y and n

`n = y - 3`

Make y the subject

`y = n + 3`

Replace y with f'(n)

`f'(n) = n + 3`