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Find the inverse of square root f(n) = n – 3.

Of(n) = (n + 3)
Of-1 (n) = yn +1
Of-1 (n) = -n° +1
Of-1 (n) = -n3 – 3

User Elvera
by
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1 Answer

12 votes

Answer:


f'(n) = n + 3

Explanation:

Given


f(n) = n - 3

Required

The inverse


f(n) = n - 3

Replace f(n) with y


y = n - 3

Swap positions of y and n


n = y - 3

Make y the subject


y = n + 3

Replace y with f'(n)


f'(n) = n + 3

User DIsoVi
by
7.0k points