231k views
5 votes
Which trig ratio would you use to solve for the missing angle measure? 5 A) Cos! 26 26 B Cos-1 5 C) Sin 26 Sin? 26 5​

Which trig ratio would you use to solve for the missing angle measure? 5 A) Cos! 26 26 B-example-1
User Pixyzehn
by
3.2k points

1 Answer

10 votes

Answer: Choice A)
\cos^(-1) (5)/(26)

You could also write
\cos^(-1) \left((5)/(26)\right) which is the same as writing
\arccos\left((5)/(26)\right)

Arccos stands for "arccosine", which is effectively the same as inverse sine. The notation
\cos^(-1) means inverse cosine.

We use the cosine rule because

cos(angle) = adjacent/hypotenuse.

isolating the angle leads to

angle = arccos(adjacent/hypotenuse)

We can think of arccosine as an operation to undo the cosine function. It's similar to how division is the opposite of multiplication.

User Ivor Prebeg
by
3.4k points