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Suppose you make coffee and it starts off just too hot to drink, so you put it in the refrigerator temporarily to cool it off. If the original temperature is 190 degrees Fahrenheit and the refrigerator is 36 degrees Fahrenheit, what will the temperature of the coffee be after 3 minutes? (k = 0.12)

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Answer:

Explanation:

f(x)= 36( 1 - 0.12)^x. F(x)= 36(0.88)^3. f(x)= 95.04 190-95.05 = 94.95 degree.

Because the temperature is going down, we will use (1-0.12) instead of (1+0.12). X=3 because it is what temperature after 3 min. x= time.

I don't understand the question that well, but please don't report me. I will fix it if I can.

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