How many molecules of manganese (IV) sulfate are there if you are given 542.32g?

asked Oct 17, 2022 235k views

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7 votes

Answer:

3.47 mol MnSO4

Step-by-step explanation:

54.94 + 32.07 + (16 × 4) = 151.01g/mol MnSO4

542.32g / 151.01g/mol = 3.47 mol MnSO4

Arun Raja answered Oct 20, 2022

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