Question

2(8x-4)-2x < 4x+12

the sign is supposed to be less than or equal to

Answer 1

`\fbox { \fbox{Solution}}`

Given

`2(8x-4)-2x < 4x+12`

Solving The Equation

`16x-8-2x < 4x+12`

Solving The Like Terms

`16x-2x-8 < 4x+12`

`= 14x-8 < 4x+12`

Adding 8 in both sides

`= 14x-8+8 < 4x+12+8`

`= 14x < 4x+20`

Bringing 4x To Left side

`= 14x-4x < 20`

`= 10x < 20`

`= 10x < 20 \\ \\ = x < (20)/(10) \\ \\ = x < \cancel (20)/(10) \\ \\ = x < 2`

Hope This Helps You

Answer 2

Answer: x < 2

Explanation:

Given expression

2 (8x - 4) - 2x < 4x + 12

Expand parentheses and apply the distributive property

16x - 8 - 2x < 4x + 12

Combine like terms

(16x - 2x) - 8 < 4x + 12

14x - 8 < 4x + 12

Add 8 on both sides

14x - 8 + 8 < 4x + 12 + 8

14x < 4x + 20

Subtract 4x on both sides

14x - 4x < 4x + 20 - 4x

10x < 20

Divide 10 on both sides

10x / 10 < 20 / 10

`\boxed{x<2}`

Hope this helps!! :)

Please let me know if you have any questions