Question

What is the change in temperature of 150.0 g of chloroform if it absorbs 1000.0 joules of heat, and the specific heat of chloroform is 0.96 J/g0C?

Answer 1

ΔT ≈ 7°C (1 sig-fig)

Step-by-step explanation:

Q = mcΔT => ΔT = Q/mc = 1000J/150g·0.96j·g·°C = 6.94°C ≈ 7°C (1 sig-fig)