Question

An envelope measures 9 inches by 4 inches. A pencil is placed at a diagonal. What is the maximum possible length of the pencil? If necessary round to the nearest tenth

Answer 1

d = 9.84 m

Explanation:

The dimensions of an envelope are 9 inches by 4 inches.

We need to find the maximum possible length of the pencil.

Let it be d. It can be calculated using Pythagoras theorem such that,

`d=√(9^2+4^2) \\\\d=9.84\ m`

So, the maximum possible length of the pencil is 9.84 m./