For what value of k is the trinomial x2 - 6x + k a perfect square?

Ross Bush asked May 1, 2022

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Ross Bush asked May 1, 2022

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19 votes

Answer:

Explanation:

$x^2-6x+k\\= x^2-6x + 9 + (-9)+k\\=(x-3)^2+k-9$

So in order this expression to be a perfect square we need k-9=0. Thus k =9.

Smfoote answered May 7, 2022

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