42.7k views
22 votes
If a-b = 7 and ab = 8. Find the value of a^3 - b^3 (a cube - b cube)​

User Imthath
by
7.8k points

1 Answer

6 votes

Answer:

511

Explanation:

a-b = 7 ____eq 1

ab = 8 ____eq 2

a = 7 + b ___eq 3

a = 8/b ___eq 4

using simultaneous equations :

7 + b = 8/b

7b + b^2=8

b^2 + 7b - 8 =0

factorize it

b^2 + 8b - b - 8 = 0

b(b+8) -1(b+8)=0

b = 1 , -8

then a = 8/1 = 8

a =8/-8 = -1

a = 8, -1

so,

a^3 - b^3

= (8)^3-(1)^3

= 511

User Loraderon
by
7.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories