Question

Solve: |x+2|−1≥5. Write your solution in interval notation.

Answer 1

nswer:

Step-by-step explanat

|x+2| - 1 ≥ 5

 |x+2| ≥ 5+1

 |x+2| ≥ 6

 x+2 ≥ 6 hoặc x+2 ≤ -6

+ với x+2 ≥ 6  x ≥ 6 – 2  x ≥ 4

+ với x+2 ≤ -6  x ≤ -6 – 2  x ≤ -8

(-∝;-8)∪(4;+∝)