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What is the solution of the system of linear equations graphed below?

What is the solution of the system of linear equations graphed below?-example-1
User Jazimov
by
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1 Answer

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12 votes

Answer: (1.125,-0.25)

Step-by-step explanation: The point that is the same for both equations is the point where they intersect. It appears from the graph to be around (1,0). We should confirm this by deriving the equation for each line and then solving them. Use the standard format: y = mx+b, where m is the slope and b the y-intercept.

I calculate the 1st line (angled down to the right) to have a slope (m) of -2 [y drops 2 for every increase of 1 for x). The y intercept is 2 (b). This equation would be y = mx+b, or y = -2x + 2.

The second line has a positive slope of 2/3 and a y intercept of -1, y = (2/3)x-1

Set these two equations equal to each other and solve for x.

-2x+2=(2/3)x-1

x = 1.125

Use that value of x to solve for y: y = -0.25

The point of intersection is therefore (1.125, -0.25)

User Agchou
by
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