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How much energy (in Joules) is required to convert 80 grams of ice at −46 °C to liquid water at 29 °C? (The specific heat of ice = 2.10 J/g°C; the specific heat of water = 4.184 J/g°C; the heat of fusion
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How much energy (in Joules) is required to convert 80 grams of ice at −46 °C to liquid water at 29 °C?

(The specific heat of ice = 2.10 J/g°C; the specific heat of water = 4.184 J/g°C; the heat of fusion = 333 J/g°C).

User WhoIsDT
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9 votes

Answer:

Hmm Use a Calculator

Step-by-step explanation:

User Vmorusu
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