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A student in Greece discovers a pottery bowl that contains 28% of its original amount of C-14 find the age of the pottery bowl to the nearest year

1 Answer

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Answer:

The age of the pottery bowl is 10523 years.

Explanation:

Amount of substance:

The amount of a substance after t years is given by the following equation:


A(t) = A(0)(1-r)^t

In which A(0) is the initial amount and r is the decay rate.

Half-life of C14.

Researching, the half-life of c-14 is 5730 years.

This means that:


A(5730) = 0.5A(0)

We use this to find r. So


A(t) = A(0)(1-r)^t


0.5A(0) = A(0)(1-r)^(5730)


(1-r)^(5730) = 0.5


\sqrt[5730]{(1-r)^(5730)} = \sqrt[5730]{0.5}


1 - r = 0.5^{(1)/(5730)}


1 - r = 0.99987903922

So


A(t) = A(0)(0.99987903922)^t

Age of the pottery bowl:

We have that:


A(t) = 0.28A(0)

We have to find t. So


A(t) = A(0)(0.99987903922)^t


0.28A(0) = A(0)(0.99987903922)^t


(0.99987903922)^t = 0.28


\log{(0.99987903922)^t} = \log{0.28}


t\log{0.99987903922} = \log{0.28}


t = \frac{\log{0.28}}{\log{0.99987903922}}


t = 10523.1

So

The age of the pottery bowl is 10523 years.

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