Find two integers whose sum is -13 and product is 42

Question

asked May 3, 2022 148k views

2 Answers

Maestro · Answer 1 · 2022-05-05T01:05:23+0000

Answer:

x+y=-13......i

xy=42........ii

from ii, x =42/y...iii

put iii in i

42/y +y =-13

(42+y²)/y=-13

42+y²=-13y

y²+13y+42=0

y²+6y+7y+42=0

(y²+6y)+(7y+42)=0

y(y+6)+7(y+6)=0

(y+7)(y+6)

y= -7 or -6

if y=-7,

x-7=-13

x=-6

if y=-6

x-6=-13

x=-7

x= -7,-6

y=-6,-7