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Find two integers whose sum is -13 and product is 42

User Dlm
by
4.5k points

2 Answers

11 votes

Answer:

x+y=-13......i

xy=42........ii

from ii, x =42/y...iii

put iii in i

42/y +y =-13

(42+y²)/y=-13

42+y²=-13y

y²+13y+42=0

y²+6y+7y+42=0

(y²+6y)+(7y+42)=0

y(y+6)+7(y+6)=0

(y+7)(y+6)

y= -7 or -6

if y=-7,

x-7=-13

x=-6

if y=-6

x-6=-13

x=-7

x= -7,-6

y=-6,-7

User Maestro
by
3.8k points
6 votes

Answer:

they are -6 and -7

Explanation:

User William Mioch
by
4.6k points