Question

H(x)=

⎩
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎨
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎧
​

x
3

x
24
​
−1
(x−1)(x+3)
​

,
,
,
​

x∈(−∞,0]
x∈(0,8]
x∈(8,∞)
​

h
(
−
3
)
=
h(−3)=h, left parenthesis, minus, 3, right parenthesis, equals

Answer 1

h(-3) = -27

Explanation:

given that h(-3)

a)

for x³

(-3)³

-27

b)

for
`(24)/(x)`-1

`(24)/(-3)`-1

-8-1

-9

c)

for (x-1)(x+3)

(-3-1)(-3+3)

0