Answer:
number 1 =
Let y=f(x)=3x−5
Clearly f(x) is one-one onto function so it is invertible.
y=3x−5 ⇒x = y+5/3
∴f −1 (x)= y+5/3
number 2=
(g-h)= 4x+3-x3-2x3
(g-h)=4(-1)+3-(-1)2-2(-x)2
(g-h)=-4+3-(-1)-2(1)
(g-h)=-4+3+1 -2
(g-h) = 2
hope that helps>3
Explanation:
1 f(-5) = 3(-5)-1= – 15 – 1 = – 16
2. h(1) = 2(1)+3=2+3=5
g(2)= 3- 4(2)=3 – 8 = – 5
3h(1) ‐ g(2) = 3 (5) – (-5) = 15 +5= 20
I hope I helped you^_^
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