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Evaluate the following when a= 1 ,b=3,and c =27 ( a) 6a^2+ 2bc-2c^1/3​

User Fire Fist
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1 Answer

9 votes

Answer:

6a^2+ 2bc-2c^1/3 = 162

Explanation:

  • a = 1
  • b = 3
  • c = 27


\rm 6 {a}^(2) + 2bc - 2 {c}^{ (1)/(3) }


= 6 {(1)}^(2) + 2(3)(27) - 2( {27)}^{ (1)/(3) }


\rm = 6 + 162 - 2 ( \sqrt[3]{27} )


\rm = 168 - 2(3)


\rm = 168 - 6


\boxed{\rm = 162}

User Suh
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