Answer:
Building C
Step-by-step explanation:
To solve this, we find the present value of each of the buildings.
Building A: We are told that it is to be Purchased for a cash price of $612,100, useful life 26 years. Thus;
PV = $612000
Building B: PV = 71490 + (71490 × ((1+r)ⁿ - 1)/(r(1+r)ⁿ)
Where,
r = 12% = 0.12
n = 26 - 1 = 25
Thus;
PV = 71490 + (71490 × (1 + 0.12)^(25) -1)/(0.12(1 + 0.12)^25)
PV = = $632196
Building C:
PV = 655200 - 6850 × ((1+r)ⁿ - 1)/(r(1+r)ⁿ)
Where;
r = 12% = 0.12
n=26
Thus;
PV = 655200 - (6850 × (1 + 0.12)^(25) -1)/(0.12(1 + 0.12)^25)
PV = $601474
Thus, the minimum PV is building C and therefore it is the one I will recommend that Brubaker Inc. locate