Answer:
12 moles of propane.
Step-by-step explanation:
From the question given above, the following data were obtained:
Volume (V) = 216 L
Pressure (P) = 184.8 KPa
Temperature (T) = 127 °C
Number of mole (n) =?
Next, we shall convert 127 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
T(°C) = 127 °C
T(K) = 127 + 273
T(K) = 400 K
Finally, we shall determine the number of mole of propane gas in the container. This can be obtained as follow:
Volume (V) = 216 L
Pressure (P) = 184.8 KPa
Temperature (T) = 400 K
Gas constant (R) = 8.314 L.KPa/Kmol
Number of mole (n) =?
PV = nRT
184.8 × 216 = n × 8.314 × 400
39916.8 = n × 3325.6
Divide both side by 3325.6
n = 39916.8 / 3325.6
n = 12 moles
Thus, 12 moles of propane is present in the cylinder