Question

Find the sum of the first six terms of a geometric
progression 2,6, 18...​

Answer 1

here,

first term(a)=2

common ratio(r)=6/2=3

Now,

sum of first six term=a(r^n-1)/r-1

=2(729-1)/3-1

=2×728/2

=728

Answer 2

2+6+18+54+162+486=728

Explanation: