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10 votes
X^2-4x+3=0 write it in standard form.

solve by completing the square.
solve by quadratic formula​

User LGB
by
8.1k points

2 Answers

8 votes

Explanation:

x²-4x+3=0

x²-4x=-3

take half of -4 square it and add it to both side

x²-4x+(-2)²=4-3

(x-2)²=1

x-2=±1

x=2±1

x=1,3

User Daniel Morell
by
8.8k points
8 votes

Answer:

x

=

2

±

7

Explanation:

there are no whole numbers which multiply to - 3

and sum to - 4

we can solve using the method of

completing the square

the coefficient of the

x

2

term is 1

add subtract

(

1

2

coefficient of the x-term

) 2 to x2 − 4 x ⇒ x 2 +2(− 2 ) x + 4 − 4 − 3 = 0 ⇒ ( x − 2 )2 − 7 =0 ⇒ ( x − 2 ) 2 = 7

take the square root of both sides

⇒ x − 2 = ± √ 7 ←

note plus or minus

⇒ x = 2 ± √ 7←

exact solutions

User Xuhcc
by
8.0k points

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